posted by Jena on .
the pressure is one atmosphere and determine the heat in joules required to produce 5.03 kg of water vapor at 100.0 °C, starting with (a) 5.03 kg of water at 100.0 °C and (b) 5.03 kg of liquid water at 0.0 °C.
for part (a) I used the equation Q=mL and L was a given value but I tried the same for part (b) but couldn't get the right answer.
For part be, remember the heat to vaporize is at a constant temp of 100C. First you have to h eat the water to that temperature.
Heattotal= heatwater + heat vaporization
= mc(100) + mL
For part b the water must be heated from 0 degrees C to 100 C then added to the heat required to vaporize it at 100 degrees C. You will need to look up the heat of vaporization.
Assume that the pressure is one atmosphere and determine the heat in .