In this website,
winter.group.shef.ac.uk/vsepr/isomers.html
Does model (A) have the most interactions... leaving model C to least reactions?
The way I read it is that model C has the most interactions and model A has the least (overall); therefore, the lone pairs go into equitorial instead of axial positions.
To determine which model has the most interactions and which one has the least interactions, we can analyze the VSEPR (Valence Shell Electron Pair Repulsion) theory for each molecule.
1. Visit the website: winter.group.shef.ac.uk/vsepr/isomers.html.
2. Scroll down until you find the section titled "H2NCl Isomers."
3. Three different models (A, B, and C) are displayed, along with their molecular structures.
4. Analyze each model based on the VSEPR theory. In VSEPR theory, lone pairs and bonded pairs of electrons around a central atom repel each other and try to maximize their distances.
5. Model A consists of a nitrogen atom at the center bonded to two hydrogen atoms and one chlorine atom. The nitrogen atom has one lone pair. Based on the VSEPR theory, the lone pair will repel the other electron pairs and distort the shape, resulting in interactions (repulsion). Therefore, Model A has interaction(s).
6. Model B also contains a nitrogen atom at the center bonded to two hydrogen atoms and one chlorine atom. Similarly, the nitrogen atom has one lone pair. By applying the VSEPR theory, we anticipate interactions due to the lone pair, identical to Model A.
7. Model C represents a different arrangement where the lone pair on the nitrogen atom is pushed into the equatorial position rather than the axial position as in Models A and B. According to the VSEPR theory, this arrangement minimizes interactions between electron pairs, resulting in less repulsion. Therefore, Model C has fewer interactions.
In conclusion, based on the VSEPR theory, Model C has the least interactions, while Model A has the most interactions.