Sunday

April 20, 2014

April 20, 2014

Posted by **Rory** on Thursday, November 16, 2006 at 7:35pm.

I thought with this sort of problem you are supposed to multipy 40 by 2 and get 80 and then come up with two factors that equal 13. If this doesn't work, you are supposed to factor out a number/variable.

Since neither of these methods work, is this problem unable to be factored, or am I mistaken?

Thanks in advance.

i thought it would be 15x3+40. I am not sure though

I don't think it can be factored. The factors of 40 are

40*1

20*2

10*4

8*5

and none of those number will work.

For

a x^2 + bx + c

calculate the discriminant:

b^2 - 4 a c.

If it is negative it cannot be factored.

In this case it is -151. The factorization involves the square root of the discriminant. If it isn't rational you won't be able to find the factorization by inspection easily either.

**Related Questions**

math help - How do you figure out a related sentence for fractions? (here is the...

help - i need help solvin this quadratic equation 2x^2+x-6=0 1/3x^2+8x-3=0 Try ...

math - Suppose you need $2.40 in postage to mail a package to a friend. You have...

math correct or not? - 1. 19 is what percent of 40 a. 19=n x 40;47.5% b. 40=19 x...

Math33333 - Please help me! Problem: x+2 x-3 _________ - _________ 2x^2+5x+2 2x^...

Calculus - relative extrema x^4-2x^2+5 so far I know how to find the derivative ...

MATH, ALGEBRA - CAN SOMEONE CORRECT THIS: lIST ALL THE FACTORS OF 16? mY ANSWER...

Algebra II - One factor of f(x) = x^3 + x^2 -22x - 40 is x + 4. Find the other ...

Math - I am having trouble figuring the appropriate expression for this problem...

math - how many proper factors does 40 have?? If you don't count 1 or 40, the ...