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September 21, 2014

September 21, 2014

Posted by **Jessica** on Thursday, November 16, 2006 at 4:52pm.

Hint: We do know that one car is 180 miles ahead of the other, so the slow car's distance can be represented by " d " and the distance of the fast car, which would be ahead, can be represented by "d + 180." The time is the same again, and can be represented by "t." This time we have two unknowns, so we need two equations, one for the fast car, and one for the slow car. Again we are using the basic formula d = rt , and substituting the values that are relevant to our situation. The equation for the slow car is: d = 55t. You write the equation for the fast car, and solve the system by substitution. Don't forget the units in your answer.

I think the hint is confusing. The problem is pretty straightforward to solve, but the hint suggests it's a difficult problem.

What you do is write the positions of the cars as:

d1 = 55 mph * t

and

d2 = 65 mph * t

respecrively. hen you calculate the distance fromone car to the next. It is

d2 - d1 = 65 mph * t - 55 mph * t =

10 mph * t = 10 miles *(t/hour)

If you equate this to 180 miles and solve for t, you find t = 18 hours.

Next time, don't read the hint. Hints are only useful for complicated problems where you would get stuck if you don't go about solving it in some particular way. There is little risk of that in High School.

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