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December 17, 2014

December 17, 2014

Posted by **student** on Thursday, November 16, 2006 at 10:55am.

Please teach me . Thank you very much.

The only integer divisor of both 24 and 49 is 1. I don't know what you mean by Q[sqrt(3)], nor the "integers of Q"

I can see why you are confused by the question. So am I. Are you sure you are stating it accurately? Perhaps if you explain what Q[sqrt(3)] is, someone can help you

I'm not sure if Euclid's algorithm is still valid for algebraic integers. If it is, then the GCD should be 1. If you use the rule:

GCD[a,b] = GCD[a, b Mod a],

you fund:

GCD[24,49] = GCD[24, 49 - 2*24] =

GCD[24,1] = 1

um... we notices that if just finding the GCD of 24 and 49, the answer is 1.

But here is about GCD of them in the integers of Q[sqrt(3)]. Are they the same?

Q mean quadratic integers. Quadratic integers are in the form of a+bsqrt(d). In here d=3.

Yes, I think it is different for algebraic numbers. I never studied this subject properly...

me too. I am taking the number theory , but the ending chapter is about quadratic integer. The lecture and book do not go in deep for this topic , but the questions are. :(

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