posted by Kuwaiti on .
A stunt pilot of mass 55.0 kg who has been diving her airplane vertically pulls out of the dive by changing her course to a circle in a vertical plane.
A)If the plane's speed at the lowest point of the circle is 95.6 m/s , what is the minimum radius of the circle for the acceleration at this point not to exceed 4.00g ?
B)What is the apparent weight of the pilot at the lowest point of the pullout?
A) V^2/R = 4 g
Solve for R
You don't need the mass M for this part.
B)With an upward acceleration of a = 4g, the apparent weight will be
W = M (g + a) = 5 M g.
g = 9.8 m/s^2 Solve for W
(M(V^2))/R=(M*(acceleration of gravity)*4(or what G cannot be acceded)