Posted by **Katrina** on Sunday, November 12, 2006 at 12:37am.

a horizontal wire is stretched between two vertical poles. when a 12.0-N weight is suspended at its center, the wire sags until the angle between its halves is 110 degrees. what are the forces exerted by each half of the wire in supporting the weight?

i don't really get the question..and how to solve it

Each half of the wire applies a tension force T at an angle of (180-110)/2 = 35 degrees to the horizontal. The sum of the vertical components of these forces equals the weight (12 N).

Thus 2 T sin 35 = 12 N

Solve for the tension force t.

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