Posted by **Dee Williams** on Thursday, November 9, 2006 at 7:05pm.

logarithms

Solve the following equations

3^x-2=6

Add 2 to both sides of the equation to start. Whatever operation you do to one side of an equation you must do to the other side as well.

3^x - 2 + 2 = 6 + 2

3^x = 8

Changing to logs:

log 3^x = log 8

x log 3 = log 8

x = log 8 / log 3

x = 1.8928 -->this is a rounded value.

This should check with the original equation.

I hope this helps.

## Answer this Question

## Related Questions

- Pre Cal - 6-x=2x+9 If you are to solve the equation for x, first try to get the ...
- MATH PLEASE CHECK IT!!2 - m-2/m-5*m+5/m-2=-1 If your problem is this: (m - 2)/(m...
- algebra--distributive - how would you do this prob. negative4-(5y+6) = negative ...
- Variable - SOLVING EQUATIONS WITH THE VARIABLE ON BOTH SIDES Solve the equation...
- Math - A=1/2H(B+b) Solve for H Let's start by getting rid of the fraction. ...
- math--pre alg - not sure i did right 3(f+2)+9=13+5f 3f+6+9 = 13+5f +9 3F+15 = 12...
- Math - q + 13 = 120 __ 8 I'm going to assume your problem is this: (q/8) + 13 = ...
- math - 2r+4=10 Well r=3 so that means 2xr=6 and 6+4=10. Hint: whenever a number ...
- Algebra - - 20> 8 +7a Solve inequalities like you would an equation, EXCEPT ...
- algerbra 1 - what is the answer to 5x-16=14-5x Just giving you the answer is not...