Monday

March 2, 2015

March 2, 2015

Posted by **Lina** on Tuesday, November 7, 2006 at 6:49pm.

Write the equation of a line perpendicular to the line y = (2/3)x - 7 and passing through the point (4,-2).

The slope of the line y = (2/3)x - 7 is 2/3. The slope of a line perpendicular to this line must be its negative reciprocal, or -3/2.

Using the point-slope form to find the other line:

y - y1 = m(x - x1)

y - (-2) = -3/2(x - 4)

y + 2 = (-3/2)x + 6

y = (-3/2)x + 4

In standard form:

(3/2)x + y = 4

**Answer this Question**

**Related Questions**

Math - Write the equation of the line in standard form: (-3, 6); m = 1/2 (1, 0...

Advanced math-ck answer, please - Write the standard form of the equation of the...

Geometry HOMEWORK HELP ME PLEASE! - Draw the triangle with vertices D(-2,1), U(4...

math,correction,&help - Write the equation of the line L satisfying the given ...

precalculus - Find (a) the equation of a line that is parallel to the given ...

Advanced Math-ck answers please - 1) Write the standard form of the equation of ...

Geometry - How do I write an equation of a line perpendicular to the graph of -...

math - Write the equation of the line that passes through the points (4, 7) and...

Algebra - I know that standard form is Ax+By=C, but I'm not really sure how to ...

Writing this equation - how do I write the equation of a line perpendicular to ...