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September 17, 2014

September 17, 2014

Posted by **Lina** on Tuesday, November 7, 2006 at 6:49pm.

Write the equation of a line perpendicular to the line y = (2/3)x - 7 and passing through the point (4,-2).

The slope of the line y = (2/3)x - 7 is 2/3. The slope of a line perpendicular to this line must be its negative reciprocal, or -3/2.

Using the point-slope form to find the other line:

y - y1 = m(x - x1)

y - (-2) = -3/2(x - 4)

y + 2 = (-3/2)x + 6

y = (-3/2)x + 4

In standard form:

(3/2)x + y = 4

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