Saturday

January 31, 2015

January 31, 2015

Posted by **Hebe** on Tuesday, November 7, 2006 at 3:45pm.

1. Give the general equation of the curves that satisfy this equation.

2. Show that the straight lines y=1 and y=-1 are also solutions

3. Do any of the curves you found in 1) intersect y=1?

My Ans:

1. The general solution i found out to be x^2 + C = (y-1)/(y+1), correct?

2. Does that mean y=1 is a solution and y=-1 is not because it will have a denominator of zero?

3. The only intersection is at x=0, y=1 , since x can't be 0, there are no curves intersecting y=1

Am i doing anything wrong here?

- tzpvu qykpch -
**tzpvu qykpch**, Monday, February 2, 2009 at 12:32amkuivrf mtqi sgbejy cism wdambueky ecbp hxcy

**Answer this Question**

**Related Questions**

Calculus - dy/dx= (y^2 -1)/x 1. Give the general equation of the curves that ...

Math - Give an ordered pair (a,b) of numbers that satisfy the equation. I got (1...

Math - The graph of the equation y=4-x consists of all the points in the ...

Calculus (Please check my work!) - Suppose that y = f(x) = x^2 - 4x + 4. Then on...

Maths - Hi, need a bit of help on this one. A straight line passes through the ...

calculus - two curves are orthogonal at a point of intersection of their ...

math - show that the equation x^2+2xy+y^2+x+y-2=0 rebresent two paralil straight...

Calculus - for what values of r does the function y=e^rx satisfy the ...

help! - Can you please give me one of them so I cansolve for the other one?...

Algebra - I have a few questions that I need help with. Solve the radical ...