Posted by
**Lindz** on
.

Suppose that the number of insects captured in a trap on different nights is normally distributed with mean 2950 and standard deviation 550.

b) Suppose that we change the location of a trap whenever it captures a

number of insects that fall in the lowest 5%. If a trap was relocated on a given night, what is the maximum number of insects that it captured?

**I don't understand what this question is asking... is there another way to word this (in terms of what i'm trying to find here?)**

They are just asking you for the "cutoff" number that is required to avoid having to move the trap. It will be the number such that 95% of the time, a larger number is caught. You get that number by integrating the normal distribution, from zero insects to whatever number gives you an integral of 5% of the total distribution. Using the tool at this website,

http://psych.colorado.edu/~mcclella/java/normal/accurateNormal.html ,

I get the answer to be 2045

Good Afternoon,

I need to subtract the raction 7 4/5 from the fraction 18 6/15 and it needs to be reduced the the lowest terms! help

Good Afternoon,

I need to subtract the fraction 7 4/5 from the fraction 18 6/15 and it needs to be reduced the the lowest terms! help