if you can't help me with my first question hopw you can help me with this one.

sec(-x)/csc(-x)=tan(x)

thanx to anyone who can help

From the definition of the sec and csc functions, and the tan function,

sec(-x)/csc(-x) = sin(-x)/cos(-x)
= tan(-x)

However, tan (x) does not equal tan (-x). They have opposite signs

Are you sure you copied the problem correctly?

4 tan x[1-tan square x] the whole divided by 1-6 tan square x+tan4 x

To solve the equation and determine if it is true, we can start by simplifying both sides of the equation.

On the left side:
sec(-x)/csc(-x) = (1/cos(-x)) / (1/sin(-x)) = sin(-x)/cos(-x)

On the right side:
tan(x)

Since we want to prove if the equation is true, we need to analyze if sin(-x)/cos(-x) is equal to tan(x). Recall that the tangent function is defined as sin(x)/cos(x).

To determine if sin(-x)/cos(-x) is equal to tan(x), we can use the identity tan(x) = -tan(-x).
Therefore, tan(x) = -tan(-x).

However, from the given equation, we see that the expression sin(-x)/cos(-x) is positive (since sec(-x)/csc(-x) is equal to it).

Since tan(x) is the negative of tan(-x), the given equation sec(-x)/csc(-x) = tan(x) is not true.

So, there seems to be an error in the initial equation or the copy. Please double-check the equation or provide more information if there are any additional variables or conditions involved.