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December 20, 2014

December 20, 2014

Posted by **berhana** on Monday, November 6, 2006 at 10:05pm.

sec^6x(secxtanx)-sec^4x(secxtanx)=sec^5xtan^3x

ec^6x(secxtanx)-sec^4x(secxtanx)=sec^5xtan^3x

Factor out a sec^5 tan and divide thru. Left is

sec^2 x = Tan^2 x

Then this should reduce to

sin^2 x = cos^4 x

take the square root of each side

sin x= cos^2 x

change the cos squared to 1-sin^2

sin^2 x + sin x -1=0

Now you have a quadratic, use the quadratic equation.

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