Thursday

March 5, 2015

March 5, 2015

Posted by **SANDRO!** on Monday, November 6, 2006 at 5:17pm.

y - 2x = -5

3y - x = 5

Solve the first equation for y.

y = 2x-5

Substitute that for y in the second equation and solve for x. Then use the value of x to substitute back into the first equation and solve for y. Post your work if you get stuck.

WOULD IT BE:

4Y-X=0?

y - 2x = -5 (equation 1)

3y - x = 5 (equation 2)

=============

Use equation 1 to solve for y as I did earlier.

y = 2x + 5

Now substitute that value of y (from equation 1) into equation 2.

equation 2 is

3y-x=5. Plug the value for y into this.

3(2x+5)-x=5

Now solve for x. Then use that value for x into equation 1 and solve for y.

Post your work if you get stuck. Not a "would it be" answer.

what is a possible point that lies on the graph

y=-2x-5

yo mama

- ALGEBRA 1!PLZ HELP! -
**celese**, Thursday, October 30, 2008 at 10:23pmwell. im failing algebra jus as u r probably if ur askin help online from random ppl. sorry i cant help.

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