Saturday

April 18, 2015

April 18, 2015

Posted by **Jen** on Sunday, November 5, 2006 at 8:44pm.

I get x < + or - sqrt(3)

So how do I write the solution?

Is it (+sqrt(3),-sqrt(3)) or (-infinity, sqrt(3))?

Why?

Thanks.

So would this work?

abs x < ( sqrt 3 )

or

- sqrt 3<x<sqrt 3

The answer is given (+sqrt(3),-sqrt(3))

I don't know the reason

fuji

**Answer this Question**

**Related Questions**

Math Help please!! - Could someone show me how to solve these problems step by ...

Calculus check - Given f(x)=x^4(2x^2-15). On what interval(s) is the graph of f ...

Calculus - Please look at my work below: Solve the initial-value problem. y'' + ...

Mathematics - sqrt 6 * sqrt 8 also sqrt 7 * sqrt 5 6.92820323 and 5.916079783 So...

Math(Roots) - sqrt(24) *I don't really get this stuff.Can somebody please help ...

Math/Calculus - Solve the initial-value problem. Am I using the wrong value for ...

Math - How do you find a square root of a number that's not a perfect square? I'...

math,algebra,help - Directions are simplify by combining like terms. x radiacal ...

math calculus please help! - l = lim as x approaches 0 of x/(the square root of...

Surds - Solve in the exact form. (sqrt of 4x+1)+(sqrt of x+1)=2 Someone showed ...