Posted by
**Jen** on
.

When I solve the inquality 2x^2 - 6 < 0,

I get x < + or - sqrt(3)

So how do I write the solution?

Is it (+sqrt(3),-sqrt(3)) or (-infinity, sqrt(3))?

Why?

Thanks.

So would this work?

abs x < ( sqrt 3 )

or

- sqrt 3<x<sqrt 3

The answer is given (+sqrt(3),-sqrt(3))

I don't know the reason

fuji