December 22, 2014

Homework Help: Inequality

Posted by Jen on Sunday, November 5, 2006 at 8:44pm.

When I solve the inquality 2x^2 - 6 < 0,
I get x < + or - sqrt(3)

So how do I write the solution?
Is it (+sqrt(3),-sqrt(3)) or (-infinity, sqrt(3))?


So would this work?

abs x < ( sqrt 3 )

- sqrt 3<x<sqrt 3

The answer is given (+sqrt(3),-sqrt(3))
I don't know the reason


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