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December 22, 2014

December 22, 2014

Posted by **Jen** on Sunday, November 5, 2006 at 8:44pm.

I get x < + or - sqrt(3)

So how do I write the solution?

Is it (+sqrt(3),-sqrt(3)) or (-infinity, sqrt(3))?

Why?

Thanks.

So would this work?

abs x < ( sqrt 3 )

or

- sqrt 3<x<sqrt 3

The answer is given (+sqrt(3),-sqrt(3))

I don't know the reason

fuji

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