A bat flying in a cave emits a sound and receives its echo 0.9 s later. How far away is the cave wall?
The distance there and back is given by
distance=velocitySound*time
We are not given velocity to solve for the problem.
The velocity of sound is something you ought to memorize.
vsound= 344 m/s at room temp, standard pressure.
516 meters
To solve this problem, we need to assume that the speed of sound in the cave is the same as the standard speed of sound at room temperature and standard pressure, which is 344 m/s. We can then use the formula for distance:
distance = velocity * time
In this case, the time is given as 0.9 s. So we can plug in the values:
distance = 344 m/s * 0.9 s
Multiplying these values, we get:
distance = 309.6 m
Therefore, the distance from the bat to the cave wall is approximately 309.6 meters.