Thursday

July 31, 2014

July 31, 2014

Posted by **Hebe** on Saturday, November 4, 2006 at 4:41pm.

1. Give the general equation of the curves that satisfy this equation.

2. Show that the straight lines y=1 and y=-1 are also solutions.

3. Do any of the curves you found in 1) intersect y=1?

i started by

dy/(y^2 -1)= dx/x

and found that

[ln(y-1) - ln(y+1)]/2 = lnx

what do i do next?

The left becomes

ln((y-1)/(y+1))

move the 2 to the right to make 2lnx or lnx^2

When y is +- 1, what is the slope? Is it that slope for all x? If so, it is a straight line.

so x^2 + C = (y-1)/(y+1) is the general equation?

how do i show that the straight lines y=1 and y=-1 are also solutions.

**Related Questions**

Calculus-check my answers please - dy/dx= (y^2 -1)/x 1. Give the general ...

Math - Give an ordered pair (a,b) of numbers that satisfy the equation. I got (1...

Math - The graph of the equation y=4-x consists of all the points in the ...

CountIblis, can i bother you - Countiblis, i know that you might be busy do you ...

Factoring - What does 3x^3-3x+2=0 come out to? How would I solve this? Is the x ...

math - show that the equation x^2+2xy+y^2+x+y-2=0 rebresent two paralil straight...

calculus - two curves are orthogonal at a point of intersection of their ...

Calculus - Consider the differential equation dy/dx=xy-y. Find d^2y/dx^2 in ...

Maths - Hi, need a bit of help on this one. A straight line passes through the ...

questions - 1.) Why are there usually two solutions in quadratic equations? 2...