Thursday
April 24, 2014

Homework Help: Calculus

Posted by Hebe on Saturday, November 4, 2006 at 4:41pm.

dy/dx= (y^2 -1)/x

1. Give the general equation of the curves that satisfy this equation.

2. Show that the straight lines y=1 and y=-1 are also solutions.

3. Do any of the curves you found in 1) intersect y=1?

i started by
dy/(y^2 -1)= dx/x
and found that
[ln(y-1) - ln(y+1)]/2 = lnx

what do i do next?



The left becomes
ln((y-1)/(y+1))
move the 2 to the right to make 2lnx or lnx^2

When y is +- 1, what is the slope? Is it that slope for all x? If so, it is a straight line.

so x^2 + C = (y-1)/(y+1) is the general equation?

how do i show that the straight lines y=1 and y=-1 are also solutions.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Calculus-check my answers please - dy/dx= (y^2 -1)/x 1. Give the general ...
Calculus (Please check my work!) - Suppose that y = f(x) = x^2 - 4x + 4. Then on...
Calculus - I am unsure of how to take the derivative of this equation. It may be...
calculus - Can you give me a good website on the topic, slope fields and ...
Calculus - How do you us implicit differentiation to solve x( y + 2 )^5 = 8 x( y...
Calculus - Follow the steps below for the given function. (Do not use mixed ...
calculus - considering that x is the independent variable in this equation: y + ...
calculus - Given: y^2+h^2=1 Find h as a function of y. If expression for dy/dx ...
calculus - Given: y^2+h^2=1 Find h as a function of y. If expression for dy/dx ...
math (differential equation) - show that y sub n=cos(ncos^-1(x)) satisfies the ...

Search
Members