Friday

October 31, 2014

October 31, 2014

Posted by **bobpursley** on Thursday, November 2, 2006 at 1:41pm.

(y-a)^2=x + b

(0-a)^2=1 + b

Now the vertex.

(y-a)^2=x +b

(2-a)^2= 0 + b

or these two equations are..

a^2= 1+b

or b= a^2 - 1 putting this into the second equation.

4-4a + a^2=a^2-1

solve for a, then go back and solve for b

none of those links help for the parabola helped.

it has a vertex of (0,2)

it intercepts the x axis at (1,0)

what is the equation and find the focus???????

Is it (y-2)^2 = x????

**Answer this Question**

**Related Questions**

algebra - I would like to have some help on this problem please. I'm so post to ...

Math does anyone know this? - y= x^2 +4x-5 x intercept- 4? y intercept- -5? ...

Maths - Given the quadratic function y =3x^2+10x-8 (i)Find the y-intercept. (ii)...

Physics or math (very simple terminology question) - "Describe the ...

Algebra - All parabolas are symmetric with respect to a line called the axis of ...

geometery - 1.given the function y=x^2-4x+5,find the following: a.vertex b....

ALGEBRA 1 - Please check for me.Without drawing the graph of the given equation ...

ALGEBRA 1 - Please check for me.Without drawing the graph of the given equation ...

Algebra - Identify the vertex and the axis of symmetry for the graph of y=5(x-2...

Math/Algebra - Please help me with this, below is a question I have to answer…...