Posted by **Jill Hefner** on Wednesday, November 1, 2006 at 4:53pm.

A BALL IS THROWN STRIAGHT UPWARD AND RETURMS TO THE THROWER'S HAND AFTER 3 SECONDS IN THE AIR. A SECOND BALL IS THROWN AT AN ANGLE OF 30 DEGREES WITH THE HORIZONTAL. AT WHAT SPEED MUST THE 2ND BALL BE THROWN SO THAT IT REACHES THE SAME HIEGHT AS THE ONE THORWN VERTICALLY?

I wish I could help but I am taking Biology this year!Sorry but um....check your Physics book!

Also,thanks for the math help!

First, find the vertical speed of ball 1.

hf=hi + vi*t +1/2 g t^2

0=0 + vi*3 + 1/2 (-9.8)*9

solve for Vi.

Then, on ball 2

ThatVi= VoSin30

solve for Vo.

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