Posted by **Jill Hefner** on Wednesday, November 1, 2006 at 4:53pm.

A BALL IS THROWN STRIAGHT UPWARD AND RETURMS TO THE THROWER'S HAND AFTER 3 SECONDS IN THE AIR. A SECOND BALL IS THROWN AT AN ANGLE OF 30 DEGREES WITH THE HORIZONTAL. AT WHAT SPEED MUST THE 2ND BALL BE THROWN SO THAT IT REACHES THE SAME HIEGHT AS THE ONE THORWN VERTICALLY?

I wish I could help but I am taking Biology this year!Sorry but um....check your Physics book!

Also,thanks for the math help!

First, find the vertical speed of ball 1.

hf=hi + vi*t +1/2 g t^2

0=0 + vi*3 + 1/2 (-9.8)*9

solve for Vi.

Then, on ball 2

ThatVi= VoSin30

solve for Vo.

## Answer this Question

## Related Questions

- Physics - A ball is thrown straight upward and returns to the thrower’s hand ...
- Physics - A ball is thrown straight upward and returns to the thrower's hand ...
- physics - A ball is thrown straight upward and returns to the thrower's hand ...
- Physics - A ball is thrown straight upward and returns to the thrower's hand ...
- Physics - A ball is thrown straight upward and returns to the thrower’s hand ...
- science - a ball is thrown straight upward and returns to the thrower's hand ...
- Physics - A ball is thrown straight upward and returns to the thrower’s hand ...
- math - A ball is thrown from the edge of a cliff with an initial velocity of 60·...
- physics - A ball thrown vertically upward is caught by the thrower after 2 ...
- physics - A ball thrown straight upward returns to its original level in 2.50s. ...