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March 1, 2015

March 1, 2015

Posted by **Mary** on Sunday, October 29, 2006 at 2:23pm.

Among the contestants in a competition are 49 women and 29 men. If 5 winners are randomly selected, what is the probability that they are all men.

The probablity of the first man is 29/78 where 29 is the number men available, and 78 is the total population

The probabliity of the second man given that one has been selected is ..

28/77

The joint probability of five is ..

29/78 * 28/77 * 27/76 * 26/75 * 25/74

If you have any questions on this, reply.

Thank you so much. I totally get it now. I have another problem like that but with 36 women and 28 men. 5 chosen randomly with the probability that they're all men. I found the answer P= .01289 .Thanks you really helped!

all men? (28)/62 * 27/61 * 26/60 and so forth.

isn't it suppose to be 28/64 where 64 is the total population of men and women?

Of course, I added wrong in my head. I have to stop doing that at my age. Thanks for reading it carefully, and finding the error. Good work.

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