assuming you have o.4g of Y(OH)3, calculate the mass of BaO2 required to react stoichiometrically to produce YBa2Cu3O7. Now calculate the mass of CuO.

Please HELP!

Write the balanced equation. Then, calculate the moles of Y hydroxide from .4 g. Then, notice from the balanced equation how many moles of Barium oxide will be required, and convert that to grams.

To calculate the mass of BaO2 required to react stoichiometrically with Y(OH)3 to produce YBa2Cu3O7, we first need to write the balanced equation for the reaction between Y(OH)3 and BaO2.

The balanced equation is:
2BaO2 + 3Y(OH)3 -> YBa2Cu3O7 + 3H2O

From the balanced equation, we can see that 2 moles of BaO2 react with 3 moles of Y(OH)3 to produce 1 mole of YBa2Cu3O7.

Now, let's calculate the moles of Y(OH)3 from the given mass of 0.4 g. To do this, we need to know the molar mass of Y(OH)3. The molar mass of Y(OH)3 can be calculated as follows:

Molar mass of Y = 88.91 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of H = 1.01 g/mol

So, molar mass of Y(OH)3 = (88.91 g/mol) + (3 × (16.00 g/mol + 1.01 g/mol))
= 88.91 g/mol + 3 × 17.01 g/mol
= 88.91 g/mol + 51.03 g/mol
= 139.94 g/mol

Now, we can calculate the moles of Y(OH)3:
moles of Y(OH)3 = mass of Y(OH)3 / molar mass of Y(OH)3
= 0.4 g / 139.94 g/mol

Next, we can use the mole ratio from the balanced equation to calculate the moles of BaO2 required to react stoichiometrically with Y(OH)3.

From the balanced equation, we know that 2 moles of BaO2 react with 3 moles of Y(OH)3. Therefore, the moles of BaO2 can be calculated as follows:

moles of BaO2 = (moles of Y(OH)3 × 2) / 3

Finally, to convert the moles of BaO2 to grams, we multiply it by the molar mass of BaO2.

Molar mass of Ba = 137.33 g/mol
Molar mass of O = 16.00 g/mol

So, molar mass of BaO2 = (137.33 g/mol) + (2 × 16.00 g/mol)
= 137.33 g/mol + 32 g/mol
= 169.33 g/mol

mass of BaO2 = moles of BaO2 × molar mass of BaO2

Now you can calculate the mass of BaO2 required to react stoichiometrically with Y(OH)3 to produce YBa2Cu3O7.

To calculate the mass of CuO, we can use the same approach. Start with the moles of Y(OH)3 calculated earlier, and use the mole ratio from the balanced equation to determine the moles of CuO. Then, convert the moles of CuO to grams by multiplying it by the molar mass of CuO.

The balanced equation shows that 2 moles of BaO2 react with 3 moles of Y(OH)3 to produce 3 moles of CuO. So, the moles of CuO can be calculated as follows:

moles of CuO = (moles of Y(OH)3 × 3) / 3

The molar mass of Cu = 63.55 g/mol
The molar mass of O = 16.00 g/mol

So, the molar mass of CuO = 63.55 g/mol + 16.00 g/mol
= 79.55 g/mol

mass of CuO = moles of CuO × molar mass of CuO

Now you can calculate the mass of CuO.