Wednesday

April 23, 2014

April 23, 2014

Posted by **413** on Tuesday, October 24, 2006 at 1:28pm.

f(x)= e^-x^2.

I got f''(x)=-2e^-x^2 + 4x^2e^-x^2

i need some help on find f''''(x)

You have

f(x) = e

f'(x) = -2x*e

f"(x) = (4x

f"'(x)= f'(x)*(4x

f(x)(-8x

f""(x) = f'(x)*(-8x

-2x*f(x)(-8x

f(x)(16x

Be sure to verify my algebra.

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