Posted by **Anonymous** on Monday, October 23, 2006 at 7:06pm.

A spinning flywheel has rotational inertia I = 402.9 kgm2. Its angular velocity decreases from 20.3 rad/s to zero in 266.6 s due to friction. What is the frictional torque acting?

Torque= MomentofInertia*angularacceleration.

You are given the moment of inertia (you named it rotational inertia). Angular acceleration is (20.3/266.3) rad/sec^2

Solve for torque.

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