posted by Anonymous on .
A spinning flywheel has rotational inertia I = 402.9 kgm2. Its angular velocity decreases from 20.3 rad/s to zero in 266.6 s due to friction. What is the frictional torque acting?
You are given the moment of inertia (you named it rotational inertia). Angular acceleration is (20.3/266.3) rad/sec^2
Solve for torque.