Farmer joe had 3 animals, he wanted to weight Lucy, Nancy and Sue. He only had a scale that started with 100kg. Now, as heavy as those animals were, none of them exceeded 100kg.so he weighted them in pairs. Lucy and Nancy weight 132 kg together and Sue and Lucy weight 137 kg together. How much did each weight individually?

You will need one more weighing. I suggest Nancy and Sue.

You have three unknowns, it will take three equations to solve for the unknowns.

sorry don't know and im really good ar math

No problem! I can help you solve this math problem step by step. Let's assign variables to the weights of Lucy, Nancy, and Sue.

Let's say the weight of Lucy is L, the weight of Nancy is N, and the weight of Sue is S.

We are given two pieces of information:
1. Lucy and Nancy weigh 132 kg together.
Therefore, L + N = 132.

2. Sue and Lucy weigh 137 kg together.
Therefore, S + L = 137.

To find the individual weights of Lucy, Nancy, and Sue, we need one more equation. We can find this equation by weighing Nancy and Sue together.

Weighing Nancy and Sue:
Since none of the animals weigh more than 100 kg, their combined weight should be less than or equal to 100 kg.

If we add the weights of Nancy and Sue together, we get: N + S <= 100.

With these three equations, we can solve for the individual weights.

Now, let's substitute the values from equation 1 and equation 2 into equation 3:
From equation 1, we have N = 132 - L.
From equation 2, we have S = 137 - L.

Substituting these values into equation 3, we get:
(132 - L) + (137 - L) <= 100.

Simplifying the equation, we have:
269 - 2L <= 100.

Moving the terms around, we have:
-2L <= 100 - 269.

Simplifying further, we have:
-2L <= -169.

Dividing both sides of the inequality by -2 (and remember to reverse the inequality because we are dividing by a negative number), we get:
L >= -169 / -2.

Simplifying, we have:
L >= 84.5.

Since the weight of an animal cannot be negative, Lucy weighs at least 84.5 kg.

Now let's substitute this value back into equation 1 to find the weight of Nancy:
L + N = 132.
84.5 + N = 132.

Subtracting 84.5 from both sides, we have:
N = 132 - 84.5.

Simplifying, we have:
N = 47.5.

Finally, let's substitute the value of Lucy (84.5) into equation 2 to find the weight of Sue:
S + 84.5 = 137.

Subtracting 84.5 from both sides, we have:
S = 137 - 84.5.

Simplifying, we have:
S = 52.5.

Therefore, Lucy weighs 84.5 kg, Nancy weighs 47.5 kg, and Sue weighs 52.5 kg.

I hope this explanation helps! Let me know if you have any further questions.