A suspension contains 2400 mg of active drug in 1000 ml waht is the percentage of drug in the final product? what is the answer?
Total mass is 1000g + 2.400g.
Percent by mass (m/m)= 2.4 /1002 * 100
The percentage of the drug in the final product is approximately 0.24% by mass.
To find the percentage of drug in the final product, you need to calculate the percent by mass.
First, calculate the total mass of the suspension:
Total mass = mass of drug + mass of solvent
Total mass = 2400 mg + 1000 ml (converted to mg)
Total mass = 2400 mg + 1000000 mg
Total mass = 10002400 mg
Next, calculate the percentage of drug in the final product (percent by mass):
Percent by mass (m/m) = (mass of drug / total mass) * 100
Percent by mass (m/m) = (2400 mg / 10002400 mg) * 100
Simplifying the fraction:
Percent by mass (m/m) = 0.00024 * 100
Percent by mass (m/m) = 0.024%
Therefore, the percentage of drug in the final product is 0.024%.
To find the percentage of drug in the final product, you need to calculate the mass of the drug and the total mass of the suspension.
Given that the suspension contains 2400 mg of active drug in 1000 ml of liquid, you first need to convert the milliliters (ml) to grams (g) since the mass of the drug is given in milligrams (mg).
To convert ml to g, you need to know the density of the liquid. Assuming the density is 1 g/ml, then 1000 ml of liquid would be equivalent to 1000 g.
Therefore, the total mass of the suspension would be:
1000 g (liquid) + 2400 mg (drug) = 1000 g + 2.4 g = 1002.4 g
To find the percentage by mass (m/m), you can use the formula:
Percent by mass (m/m) = (mass of drug / total mass) * 100
Substituting the values, we get:
(mass of drug) = 2.4 g
(total mass) = 1002.4 g
Percent by mass (m/m) = (2.4 g / 1002.4 g) * 100
Calculating this expression, we find that the percentage of drug in the final product is approximately:
0.2395% (rounded to four decimal places)