Posted by **Jasmine202005** on Sunday, October 22, 2006 at 8:55pm.

How do i solve inequalitites with three variables. I still can't figure it outplease help.

x+y=1

y-z=-3

2x+3y+z=1

THE ANSWERS ARE3,-2,1 HOW DID THEY GET THAT ANSWER.

This can be solved a number of ways.

1) subsitition

2) determinants

3) matricies.

Substution:

x= 1-y

y= z+3 or x= 1-z-3

In the third equation , put those two things for x, and y.

2x+3y+z=1

then solve for z. Then go back and solve for x and y.

I've done that already such as

the book states the following

that the answer is -x-y=-1

how did they get there after adding equation 2 and three

Substitute x = 1-y and z = y+3 in the third equation. Then you get an equation in y only:

2(1-y) + 3y + (y+3) = 1

2y + 5 = 1

y = -2

Then use the equations for x and z again.

x = 1-(-2) = 3 etc.

## Answer This Question

## Related Questions

- to annonymus can you help me with math - How do i solve inequalitites with three...
- TO DRWLS/MATH HELP PLEASE - How do i solve inequalitites with three variables. I...
- math - How do i solve inequalitites with three variables. I still can't figure ...
- Math Help Please - How do i solve inequalitites with three variables. I still ...
- a.p. calculus help please! - My a.p. calculus teacher doesn't know how to do ...
- Algebra - I was given this problem to solve and no matter what order I multiply ...
- Basic Math - I forgot how to solve for two variables... Please check if I solved...
- Precalculus - I asked this yesterday but I was told my answer was incorrect by ...
- Quadratic Functions2 - Determine the standard form of a quadratic function whose...
- Radicals3 - State the restrictions on the variables and then simplify each of ...

More Related Questions