If a^3 = x^2
what is a^2y+1 = x^6, solving for y
You would have
(x2)3 = x6 = a9
so 9 = 2y+1
Do you see why?
do u mean
a^(2y) + 1 = x^6
or
a^2 * y + 1 = x^6
a^(2y+1) = x^6
To solve for y in the equation a^(2y+1) = x^6, you can use the properties of exponents. Here's the step-by-step explanation:
1. Start with the equation a^(2y+1) = x^6.
2. Rewrite x^6 as (x^2)^3 using the property (a^m)^n = a^(m*n). So now the equation becomes a^(2y+1) = (x^2)^3.
3. Apply the property (a^m)^n = a^(m*n) again to simplify the equation further. Now we have a^(2y+1) = x^6 = (x^2)^3 = (x^(2*(3))).
This means that 2y+1 = 2*3, since the bases (a and x) are equal.
4. Simplify the right side of the equation: 2y+1 = 6
5. Subtract 1 from both sides to isolate the 2y term: 2y = 6 - 1 = 5.
6. Finally, divide both sides by 2 to solve for y: y = 5/2.
So, the solution for y is y = 5/2.