Posted by **Jen** on Friday, October 20, 2006 at 9:53pm.

How to find the exact value of

lim (2^h - 1)/ h

h->0

Thanks in advance.

If you use

lim dx->0 of [f(a + dx) - f(a)]/dx = f'(a)

and recognize 1=2<sup0.

Then use f(x)=2

^{x}
Thus lim dx->0 [2

^{0+dx} - 2<sup0]/dx = f'(0).

This means find d/dx 2

^{x} and evaluate at x=0.

You can think of the dx as delta x, or increment of x.

I'm not sure if you've used L'Hospital's rule or not, but that's another way you could solve this problem too.

## Answer This Question

## Related Questions

- Derivatives - What is the fourth derivative of f(x)= e^-x^2. I got f''(x)=-2e^-x...
- Inter. Algebra - Count Iblis what is the answer to 2 square root sign 18x? The ...
- Powers in Math - (5a^3b^4)^2=? *I don't get this one...PLease Help! (5a3b4)2= (5...
- Calculus - Use implicit differentiation to find the slope of the tangent line to...
- Property of logarithms - Using property of logarithms, how do I prove derivative...
- math-volume - I'm confused with how to solve this problem, so help would be ...
- help - Y^3Y/Y^-2 If you post with the correct word in the Subject line, you'll ...
- math,algebra - I'm not understanding so the answer should read as follows and ...
- Chemistry - Sorry for posting this again, I don't know if the question was ...
- Math - If a^3 = x^2 what is a^2y+1 = x^6, solving for y You would have (x2)3 = ...

More Related Questions