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December 22, 2014

December 22, 2014

Posted by **Jen** on Friday, October 20, 2006 at 9:51pm.

First observe that ln(kx) = ln(k) + ln(x) then take derivatives. The ln(k) is simply a constant so it goes away. You could also derive it as

d/dx ln(kx) = 1/kx * k by the chain rule.

To see that the derivative of ln(x) is 1/x here's a brief proof.

If you have y=ln(x) then

e

dx/dy = e

d/dy e

So 1/dx/dy = dy/dx = 1/e

This assumes that you know

d/du e

what are you doing please give alghorthm problums

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