# TRig WIth LoGs help1!!

posted by
**ashley**
.

i have problem i can't solve and the book is no help.. anyone got osme hints or somehting i could start off doing?

the problem is...

Solve for x: log(x^3)= (log x)^3

Rewrite it as 3 log x = (log x)^3

The use algebra (divide each side by log x) to get

(log x)^2 = 3

log x = (+ or -) sqrt 3

(There are two solutions)

When log x = sqrt 3,

x = e^(sqrt 3) = 5.652...

When log x = -sqrt 3,

x = e^-sqrt3, x = 0.1769...

There are actually 3 solutions, when you divided through by the log x you eliminated one of them. Try x=1 too.

sin 27 degrees = x \ 8