posted by adam! on .
the following sequence is geometric:
4/3, 4/9, 4/27....
determine the general term, tn and the term t10
so the general term is:
(4/3)x (1/3) ^n
so the tenth term is:
is this correct? thanks!
You have one too many factors of three in the denominator.
a = 4/3, r=1/3 so t10=(4/3)*1/39 = 4/310