# math+ check!

posted by
**adam!**
.

the following sequence is geometric:

4/3, 4/9, 4/27....

determine the general term, tn and the term t10

so the general term is:

(4/3)x (1/3) ^n

so the tenth term is:

4/177147

is this correct? thanks!

You have one too many factors of three in the denominator.

a = 4/3, r=1/3 so t_{10}=(4/3)*1/3^{9} = 4/3^{10}