Posted by **adam!** on Thursday, October 19, 2006 at 12:01pm.

the following sequence is geometric:

4/3, 4/9, 4/27....

determine the general term, tn and the term t10

so the general term is:

(4/3)x (1/3) ^n

so the tenth term is:

4/177147

is this correct? thanks!

You have one too many factors of three in the denominator.

a = 4/3, r=1/3 so t

_{10}=(4/3)*1/3

^{9} = 4/3

^{10}## Answer this Question

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