Homework Help: math+ check!

Posted by adam! on Thursday, October 19, 2006 at 12:01pm.

the following sequence is geometric:
4/3, 4/9, 4/27....
determine the general term, tn and the term t10

so the general term is:
(4/3)x (1/3) ^n

so the tenth term is:
4/177147

is this correct? thanks!

You have one too many factors of three in the denominator.
a = 4/3, r=1/3 so t₁₀=(4/3)*1/3⁹ = 4/3¹⁰

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