man alive! can someone check for me?
posted by george on .
I am so bad when it comes to mathI I think I am slow! okay so my question is :
a recrusive sequence is defined by tn= 2tn1, where t1= 5
define the first five terms of this sequnce:
so would I go like this to figure them out:
2tn1, where t1= 5
so
2(5)(11)= 0
so the frist 5 are: 0, 10, 20, 30,40
am I correct or am I doing it horribley wrong?
okay there is a part b!
it says would the points of the sequence, (n,Tn), lie on the graph of an exponentail function, linear function or neithr?
I would have to say neither
am I wrong?
You have t_{n} = 2t_{n1}  1, where t_{1}= 5
I think your second term is wrong.
t_{2} = 2t_{1}  1 =2*51 = 9
t_{3} = 2t_{2}  1 =2*91 = 17
t_{4} = 2t_{3}  1 =2*171 = 33
You're not "horribly" wrong, but you probably just need to see how to get started.
The fist few points look like
n T_{n}
1

okay now can anyone hellp me too

i also need help