oka so the question is as follows:

for the geometreic sereis 8+48+288+... find the sum of the first ten terms, s 10

so I would use the formula:
sn= a(1-r^n)/ 1-r
were
a= 8
r= 48
n= 10

8(1-(48)^10)/1-48

I get lost I don't know how to arrive to the answer from here! but is the rest correct?

No. r is 6. Notice 8*6= 46, 48*8= 288, etc.

Other wise, it is ok.

You are on the right track, but there is a mistake in determining the common ratio (r) for the geometric series. Let me correct it for you.

For a geometric series, the general formula for the nth term is given by: an = a * r^(n-1), where a is the first term and r is the common ratio.

In the given series, we have:
a = 8 (first term)
an = 288 (tenth term)
n = 10

We can use this information to find the common ratio (r).
288 = 8 * r^(10-1)
288 = 8 * r^9
r^9 = 36

To solve for r, we can take the ninth root of both sides:
r = ∛(36)

Now that we have the correct value for r, we can plug it into the formula for the sum of the first n terms, Sn:
Sn = a * (1 - r^n) / (1 - r)

Plugging in the values:
a = 8
r = ∛(36)
n = 10

Sn = 8 * (1 - (∛36)^10) / (1 - ∛36)

Now, you can calculate the value of Sn using a calculator or by simplifying the expression.