A team of dogs is pulling a sled that has a load of 2500 kg at a constant speed of 5.0 m/s. The coefficient of kinetic friction between the sled and the snow is 0.10. What is the horizontal force the dogs are exerting on the loaded sled?

The horizontal force is equal to the weight of the sled times mu.

Fhorizontal=mu*mg

When speed is constant, that means acceleration is zero.
Netforce=ma=0
fhorizont - force friction=0

The force of friction can be calculated using the equation:

Force of friction = coefficient of kinetic friction * normal force

In this case, the normal force is equal to the weight of the sled, which can be calculated as:

Weight = mass * gravity

Given that the mass of the sled is 2500 kg and the acceleration due to gravity is 9.8 m/s^2:

Weight = 2500 kg * 9.8 m/s^2

Now we can calculate the force of friction:

Force of friction = 0.10 * Weight

Next, we can calculate the horizontal force exerted by the dogs:

Horizontal force = Force of friction

Therefore, the horizontal force the dogs are exerting on the loaded sled is equal to the force of friction, which can be calculated using the weight and the coefficient of kinetic friction.

To find the horizontal force the dogs are exerting on the loaded sled, we need to consider the forces acting on the sled.

First, let's calculate the force of friction. The coefficient of kinetic friction (mu) is given as 0.10, and the weight of the sled (mg) can be calculated using the formula: weight = mass * gravity.

Given that the load on the sled is 2500 kg and the gravity is approximately 9.8 m/s², we can calculate the weight as follows:

Weight = 2500 kg * 9.8 m/s² = 24500 N

Now, we can substitute the values into the formula for force of friction:

Force of friction = mu * weight

Force of friction = 0.10 * 24500 N = 2450 N

Next, we know that the net force acting on the sled is zero since the speed is constant. Therefore:

Net force = Fhorizontal - Force of friction = 0

Rearranging the equation, we can find the horizontal force:

Fhorizontal = Force of friction

So, the horizontal force the dogs are exerting on the loaded sled is equal to the force of friction, which is 2450 N.

Fhorizontal = Ffriction

Fhorizontal = mu*mg

Fhorizontal = 0.10*2500kg*9.8m/s^2

Fhorizontal = 2500 N