physics
posted by Liz on .
At what altitude above the Earth's surface would your weight be threefifths of what it is at the Earth's surface? Assume re = 6.371 10^3 km.
If weight decreases as the inverse square of distance, then
3/5= (re/r)^2
where r is the distance from the center of earth to the spot you are interested.
altitude = r  re

1849.6

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How far (in meters) above the earth's surface will the acceleration of gravity be 18.0 % of what it is on the surface?

8225 km