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Posted by on Monday, October 16, 2006 at 7:09pm.

At what altitude above the Earth's surface would your weight be three-fifths of what it is at the Earth's surface? Assume re = 6.371 10^3 km.


If weight decreases as the inverse square of distance, then

3/5= (re/r)^2

where r is the distance from the center of earth to the spot you are interested.

altitude = r - re

  • physics - , Wednesday, February 13, 2008 at 2:05am

    1849.6

  • jmtugy vjos - , Monday, February 9, 2009 at 1:04am

    sgwm kwxrp gsyxnful uylfvkor pdzquges fidjprngx oedn

  • physics - , Thursday, March 15, 2012 at 6:15pm

    How far (in meters) above the earth's surface will the acceleration of gravity be 18.0 % of what it is on the surface?

  • physics - , Friday, October 11, 2013 at 2:19pm

    8225 km

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