Posted by **Liz** on Monday, October 16, 2006 at 7:09pm.

At what altitude above the Earth's surface would your weight be three-fifths of what it is at the Earth's surface? Assume re = 6.371 10^3 km.

If weight decreases as the inverse square of distance, then

3/5= (re/r)^2

where r is the distance from the center of earth to the spot you are interested.

altitude = r - re

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