Thursday

April 17, 2014

April 17, 2014

Posted by **Kimberly** on Sunday, October 15, 2006 at 9:58pm.

Suppse n is the number of eggs the man has to begin with. At the first toll he gives away

(1/2)n + 1/2 so he has

n - ((1/2)n + 1/2) = (1/2)n - 1/2 left

At the second toll he gives away

(1/2)((1/2)n - 1/2) +1/2 = (1/4)n + 1/4 so he has

((1/2)n - 1/2) - (1/4)n + 1/4 = (1/4)n -1/4 left

Finally he gives away

(1/2)((1/4)n -1/4) + 1/2 = (1/8)n +3/8

and has none left so

(1/4)n -1/4 = (1/8)n +3/8 so

(1/8)n = 5/8 and n = 5.

Now test this

If he starts with 5 eggs and gives away half and a half egg then

5 - 2.5 -.5 = 2 eggs

Next he gives away 1 egg and a half egg so he has

2 - 1 -.5 = .5

At the third stop all he has is half an egg so that's all he can give away.

Hopefully I read your problem correctly. Since I seem to have worked your problem completely find another one similar to it in your text and work that for practice.

Thank you very much!

place the fractions 1/2,19/20/4/5,7/8,3/4,1/12,1/3,3/10 from least to greatest

i do not get algebra math. One of the questions on the homework is twice a number called f. I don't get that!

i dont under stand dividing fractions and mixed numbers i dont even understand fractions at all !

help! help !help!

find the percent of increase from $24.00 to $29.00. round to the nearest hundreth.

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