Saturday
March 28, 2015

Homework Help: chemistry

Posted by Anonymous on Sunday, October 15, 2006 at 9:38pm.

At 9.20 cm cubed air bubble forms in a deep late at a depth where the temperature and pressure are 6 degress Celcius and 4.50 atm, respectively. Assuming that the amount of air in the bubble has not changed, calculate its new volume at STP.


Use the combined gas law for this:

P1V1/T1 = P2V2/T2

change the temps to Kelvins.


With anonymous answering anonymous I'll just agree that p1v1/t1 = p2v2/t2 is the formula to use and remember to change T to Kelvin
C _ 273 = K.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry - A snorkeler takes a syringe filled with 16 mL of air from the ...
Physics - An air bubble of volume 15 cc is formed at a depth of 50 m in a lake. ...
Chemistry - The adult blue whale has a lung capacity of 5.0*10^3L. Calculate the...
Physics - A scuba diver takes a tank of air on a deep dive. The tank's volume is...
chemistry - use a combustion reaction of liquid ethanol( C2H5OH) an air as a ...
Chemistry - a diver exhales a bubble with a volume of 250 mL at a pressure of 2....
chemistry - an air bubble is released at the bottom of a lake where the ...
Physics - A bubble of air, 0.010 m^3 in volume, is formed at the bottom of a ...
Physics (12th Grade) - An air bubble of volume 15 cc is formed at a depth of 50 ...
College Chemistry - When determining the vapor pressure of water, the bubble ...

Members