Rationalize each denominator.

6 + square root of 2
____________________________

square root of 3

PLZ HELP..dont kno how to do this question.plz explain..thanks

You have
(6 + sqrt(2))/sqrt(3)
multiply that by sqrt(3)/sqrt(3) to
get
[(6 + sqrt(2))*sqrt(3)]/3 and simplify

To rationalize a denominator, just multiply the numerator and denominator by the root of the number in the denominator. In this problem, multiply both numerator and denominator by (sq rt 3)/(sq rt 3), then simplify if possible.

Answer this Question ssc 7class Question construct a isosceler triangle

To rationalize the denominator, we need to eliminate the square root from the denominator. In this case, the denominator is square root of 3.

To do this, we multiply the numerator and denominator by the square root of 3:

[(6 + sqrt(2)) * sqrt(3)] / (sqrt(3) * sqrt(3))

This simplifies to:

[(6*sqrt(3)) + (sqrt(2)*sqrt(3))] / 3

Further simplifying:

[6sqrt(3) + sqrt(6)] / 3

So, the rationalized denominator of the expression (6 + square root of 2) / square root of 3 is 6sqrt(3) + sqrt(6) divided by 3.