ok im having a bit of a problem rationalizing denominators.
i have 2 to the root of 3 +4 divided by the root of 3.
I have tried multiplying the top and bottom by the root of 3 and the answer, but then i get stuck at this part. Do i multiply 4 by 4 and make it a root? or am i doing something wrong here?
the answer at the back of the book is 6 root 3+ root 6 over 3
Plz help, this is due 2morrow
Do this. I used my calculator and evaluated 2 to the sq root 3 + 4 divided by the sq root 3 and found 5.6314 for an answer. Then I took the answer you gave that appears in the back of the book and I found 11.2088. Check your answer with the calculator and see what you get. Verify my numbers.The answer in the back of the book may be wrong.
To rationalize the denominator of the fraction 2√3 + 4 / √3, you can follow these steps:
Step 1: Multiply the numerator and denominator by the conjugate of the denominator.
The conjugate of √3 is -√3, so you multiply the numerator and denominator by -√3:
(2√3 + 4) * (-√3) / (√3 * -√3)
This simplifies to:
-2√3 * √3 - 4√3 / 3
Step 2: Simplify the expression.
-2√(3 * 3) - 4√3 / 3
-2√9 - 4√3 / 3
-2 * 3 - 4√3 / 3
-6 - 4√3 / 3
Step 3: Combine like terms.
(-6/3) - (4√3 / 3)
-2 - (√3 / 3)
So the simplified expression is -2 - (√3 / 3).
Please note that the answer you provided from the back of the book, 6√3 + √6 / 3, is different from the expression you initially provided. Double-check the problem you are trying to solve or provide additional information if there is a different question you need help with.