Post a New Question

Algebra

posted by on .

Simplify each expression. Assume that no denominators are zero. Write each answer without using negative exponents.

The ^'s mean they're exponents

y^-3y^-4y^0
------------ <- division
(2y^-2)^3


numerator: y^-3y^-4y^0 = y^(-3-4)= y^-7

denominator: 2^3 * y^-6 = 8y^-6

numerator/denom= y^-7/8y^-6= 1/8 * y^(-7+6)

= 1/8 y^-1= 1/(8y)



I would multiply the denominator by itself three times, then move the terms with negative exponents up or down, changing the sign of the exponent, then combine terms. I hope this helps.

  • Algebra - ,

    7/8y-6=8

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question