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August 2, 2014

August 2, 2014

Posted by **Katie** on Sunday, October 15, 2006 at 4:33pm.

The ^'s mean they're exponents

y^-3y^-4y^0

------------ <- division

(2y^-2)^3

numerator: y^-3y^-4y^0 = y^(-3-4)= y^-7

denominator: 2^3 * y^-6 = 8y^-6

numerator/denom= y^-7/8y^-6= 1/8 * y^(-7+6)

= 1/8 y^-1= 1/(8y)

I would multiply the denominator by itself three times, then move the terms with negative exponents up or down, changing the sign of the exponent, then combine terms. I hope this helps.

- Algebra -
**rosalinda**, Wednesday, October 29, 2008 at 4:22pm7/8y-6=8

- Algebra -
**rosalinda**, Wednesday, October 29, 2008 at 4:27pm7/8y-6=8

- Algebra -

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