Homework Help: Integration

Posted by Vidal on Sunday, October 15, 2006 at 2:06am.

Intergrate Ąė sec^3(x) dx

could anybody please check this answer. are the steps correct? thanks.

= Ąė sec x d tan x
= sec x tan x - Ąė tan x d sec x
= sec x tan x - Ąė sec x tan^2(x) dx
= sec x tan x + Ąė sec x dx - Ąė sec^3(x) dx
= sec x tan x + ln |sec x + tan x| - Ąė sec^3(x) dx
=Ąė sec^3(x) dx = (1/2)(sec x tan x + ln |sec x + tan x|) + C1

Ąė [3x sin x/cos^4(x)] dx
= -3 Ąė [x/cos^4(x)] d cos x
= Ąė x d sec^3(x)
= x sec^3(x) - Ąė sec^3(x) dx
= x sec^3(x) - (1/2) sec x tan x - (1/2) ln |sec x + tan x| + C2

I'm not sure if your integration is correct or not, not all of your symbols converted to ASCII. I plugged sec³(x) into a piece of software and got an answer that looks slightly different from yours, but I'm not positive. If you still need help with this post a new question so it's easy to find.

Integration - 2+3, Friday, December 7, 2007 at 6:30am
5
egypt-german univerty in cairo-sherif.el-sayed@student.guc.edu.eg - sherif, Tuesday, March 4, 2008 at 12:07pm
s=integral
let i=S(sec^3x)dx
i=S(sec^3x)=S(sec^2x.secx).dx
=tanxsecx-S(tan^2x.secx)dx=
tanxsecx-S(sec^2x-1)secx.dx=
tanxsecx-S(sec^3x)dx+S(secx)dx
2i=tanxsecx+ln|secx+tanx|+x
i=(tanxsecx+ln|secx+tanx|+c)(0.5)
- lstem jxbsi - lstem jxbsi, Sunday, February 1, 2009 at 3:19pm
  wpjceq gcifns hoxnis ytxuwoz plfm zuonie kwhbemp

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