How would you would graph the linear equation y = -2x + 6?
First plot the point (6,0) and then count up two and to the right 1.
First plot the point (6,0) and then count down two and to the right 1
First plot the point (0,6) and then count up two and to the right 1
First plot the point (0,6) and then count down two and to the right 1
What's your answer?
i thought it was the second one
almost, but not quite.
In this equation, what is the y-intercept?
6?
That's right!!
Now what point is a y-intercept of 6?
Is it (6,0) or (0,6)??
0,6
Right!!!!!!!!!!!!!!!!!!!!!!
So which answer is correct?
the 3rd one?
OK. so point (0,6) is correct. Now, let's deal with the slope. In your equation, what is the slope?
[5x-2]=8? a 6/5 b1/2 c _6/5 d _1
The slope in the equation y = -2x + 6 is -2.
Great!! Now that we know the slope is -2 and the y-intercept is (0,6), we can graph the linear equation.
To graph the linear equation, we start by plotting the y-intercept point (0,6), which is the point where the graph intersects with the y-axis.
Next, we use the slope to find another point on the line. The slope of -2 means that for every increase of 1 in the x-coordinate, the y-coordinate decreases by 2.
So, starting from the y-intercept (0,6), we go down 2 units and then to the right 1 unit. This gives us the point (1,4).
Now we can draw a straight line through these two points to represent the linear equation y = -2x + 6 on the coordinate plane.
Therefore, the correct answer is the first one: First plot the point (6,0) and then count up two and to the right 1.