Posted by **Spirit** on Thursday, October 12, 2006 at 3:58pm.

how do you find the isoperimetric quotient of an n sided figure?

my side lengths are 5cm

i have split it in to triangles so

360/n

is the central angle

then to work out area of singular triangle its 1/2 base times height

height is something like

tan 180/n =2.5 /height length

please help i get stuck here

The sum of the interior angles is (180)(n-2). So each angle in your triangle is half that, divided by n

angle= 90/n * (n-2)

height= 2.5 tan (90/n (n-2))

Put in n, and you have height.

area for the polygon then is n*area of each triangle, where the area of each triangle is 1/2 bh= 1/2 *5*habove.

I need help to answer this question. (n-2)*180=90

## Answer this Question

## Related Questions

- geomerty - The following triangles, Ä ABC and Ä DEF, are congruent. abc 67....
- Math - Determine the number of triangles that could be drawn with the given ...
- maths - 1.how many non congruent right triangles with positive integer leg ...
- physics - On an aerial photograph of a triangular piece of land the lengths of ...
- math - The shorter diagonal of a rhombus is 10 inches long, and the angle the ...
- math help - An engineer is required to survey a nonrectangluar plot of land but ...
- math - Find the exact value of cos 300 degrees. thanks guys cos 300 = 1/2 = 0....
- Geometry - We're learning about classifying triangles with Side-Angle-Side, ...
- Math - If the scale factor from a small figure to a large figure is given as a ...
- Geometry - x ________________<20* |<90* y | |<70* (hypotenuse length ...

More Related Questions