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October 31, 2014

October 31, 2014

Posted by **Spirit** on Thursday, October 12, 2006 at 3:58pm.

my side lengths are 5cm

i have split it in to triangles so

360/n

is the central angle

then to work out area of singular triangle its 1/2 base times height

height is something like

tan 180/n =2.5 /height length

please help i get stuck here

The sum of the interior angles is (180)(n-2). So each angle in your triangle is half that, divided by n

angle= 90/n * (n-2)

height= 2.5 tan (90/n (n-2))

Put in n, and you have height.

area for the polygon then is n*area of each triangle, where the area of each triangle is 1/2 bh= 1/2 *5*habove.

I need help to answer this question. (n-2)*180=90

- maths please help -
**Anonymous**, Saturday, October 8, 2011 at 7:56pmIf a triangle has a height of 12 in. and a base of 5 in., what is its area?

A. 60 sq. in.

B. 45 sq. in.

C. 30 sq. in.

D. 90 sq. in.

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