Posted by Spirit on .
how do you find the isoperimetric quotient of an n sided figure?
my side lengths are 5cm
i have split it in to triangles so
360/n
is the central angle
then to work out area of singular triangle its 1/2 base times height
height is something like
tan 180/n =2.5 /height length
please help i get stuck here
The sum of the interior angles is (180)(n2). So each angle in your triangle is half that, divided by n
angle= 90/n * (n2)
height= 2.5 tan (90/n (n2))
Put in n, and you have height.
area for the polygon then is n*area of each triangle, where the area of each triangle is 1/2 bh= 1/2 *5*habove.
I need help to answer this question. (n2)*180=90

maths please help 
Anonymous,
If a triangle has a height of 12 in. and a base of 5 in., what is its area?
A. 60 sq. in.
B. 45 sq. in.
C. 30 sq. in.
D. 90 sq. in.