Posted by
**kevin** on
.

The plates of a parallel plate capacitor each have an area of 0.40 m2 and are separated by a distance of 0.02 m. They are charged until the potential difference between the plates is 3000 V. The charged capacitor is then isolated.

How much work is required to move a –4.0 ìC charge from the negative plate to the positive plate of this system?

Work= force*distance= Eq*distance=Volt/distance*q*distance= Vq

So the work is Volts times charge.

thanks i though it was somnethin differnt cause they gave the distance and the area