Posted by
**Lan** on
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When 3.78 g of nonvolatile solute is dissolved in 300.0 g of water, the freezing point depression is 0.646 o C. Calculate the molar mass of the solute. The cryoscopic constant of water is 1.86 K kg mol -1.

When 3.78 g of nonvolatile solute is dissolved in 300.0 g of water, the freezing point depression is 0.646 o C. Calculate the molar mass of the solute. The cryoscopic constant of water is 1.86 K kg mol -1.

DeltaTf= molality*Kf

.646=molrSolute/.3 * 1.86

.646=3.78/molmass/.3 * 1.86

solve for molmass.