# Algebra HELP!!

posted by
**Margie**
.

Write the equation of the line that contains the points (2, 2) and (-3, 12).

Here is part of the answer. Can you identify the missing part?

y = -2x + ___

I think it's 12

You've got the slope so use

y-y1=m(x-x1) where (x1,y1) is either point.

If you use (2,2), then y-2=-2(x-2)

I don't think it's 12, but verify this yourself.

I don't understand!Can you explain it better please?

I don't get it either!!

This is not a very good format for teaching, it's designed for helping. You both need to learn the basic formulas and concepts.

Slope is the change in y over x as you move along a line. The y intercept is where the line crosses the y-axis.

In the formula y=mx+b m is slope and b is the intercept.

If you're given a point and the slope you use the point slope form of the line which is

y-y1 = m(x-x1) where (x1,y1) is the given point and m is the slope; x and y are simply variables.

Another way to answer the question

Write the equation of the line that contains the points (2, 2) and (-3, 12).

Here is part of the answer. Can you identify the missing part?

y = -2x + ??

would be to substitute either point and solve for the ?? as

2= -2*2 + ?? or 6=?? so the intercept is 6.

oh so the answer is......y=2x+6???

I think that's it?Or am I suppposed to multiply!!

Yes, that's the correct answer. Test it to be sure.

sure

what is the answer for this (-1,-1), slope = 2