Determine the final velocity of a proton that has an initial velocity of 2.35 X 105 m/s, and then is accelerated uniformly in an electric field at the rate of –1.10 X 10 to the 12 power m/s2 for 1.50 X 10 to the negative 7 power seconds.
Vfinal= Vinitial + acceleration*time
Watch your units.
To solve this problem, you can use the equation:
Vfinal = Vinitial + acceleration * time
Given values:
Vinitial = 2.35 * 10^5 m/s
acceleration = -1.10 * 10^12 m/s^2 (since it is a negative acceleration, it means the proton is decelerating)
time = 1.50 * 10^-7 s
Now, plug in the values into the equation:
Vfinal = (2.35 * 10^5 m/s) + (-1.10 * 10^12 m/s^2) * (1.50 * 10^-7 s)
First, perform the multiplication:
Vfinal = (2.35 * 10^5 m/s) + (-1.65 * 10^5 m/s)
Next, simplify the addition:
Vfinal = -0.3 * 10^5 m/s
Since -0.3 * 10^5 can be simplified as -3 * 10^4, the final velocity of the proton is:
Vfinal = -3.0 * 10^4 m/s
Therefore, the final velocity of the proton is -3.0 * 10^4 m/s.