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March 31, 2015

March 31, 2015

Posted by **Rose** on Monday, October 9, 2006 at 3:50pm.

(cscX-cotX)^2=1-cosX/1+cosX

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sorry i cant help you

(cscX-cotX)=1/sinX - cosX/sinX = (1-cosX)/sinX

If you square this you have (1-cosX)^2/(sinX)^2

Now use (sinX)^2 = 1 - (cosX)^2 to get

(1-cosX)^2 / 1 - (cosX)^2 =

[(1-cosX)*(1-cosX)]/[(1 - cosX)*(1 + cosX)

Then simplify.

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