What is the antiderivative of e^2x? I know the antiderivative of e^x is e^x. Would e^2x's antiderivative still be e^2x??

You want F(x) such that F'(x)=e^2x
Try F = (1/2)e^2x + C

=(e^2x)/2

=(e^2x)/2

what is the anti derivative of

70e^-.6t

70/-.6 times e^.6t

wouldnt it be 70/-.6 times e^-.6t?

ilove men

I love women.

dawdawdawd

blue

green
red
yellow
brown
black
white
indigo
violet
purple
pink
scarlet

hope this helps :)

the answer is 7

To find the antiderivative of e^2x, you can use the power rule of integration.

The power rule states that if you have an expression of the form x^n, where n is a constant (not equal to -1), the antiderivative is (1/(n+1))x^(n+1) + C, where C is the constant of integration.

In this case, you have e^2x, where the exponent is 2x. To apply the power rule, let's rewrite it as (e^2)^x.

Since the base is a constant (e^2), you can treat it as a constant term. Applying the power rule, you would integrate (e^2)^x as (1/(2+1))(e^2)^x + C, which simplifies to (1/3)(e^2x) + C.

So, the antiderivative of e^2x is (1/3)(e^2x) + C, where C is the constant of integration.