Posted by **Tezuka** on Friday, October 6, 2006 at 2:49pm.

A rectangle is bounded by the x-axis and the semicircle y=ã(25-x^2).

Question is, what length and width should the rectangle have so that its area is a maximum, and what is the maxuimum area?

Area= length*width

= 2x*y= 2x*sqrt(25-x^2)

Now, take that, differentiate it, set to zero, and solve for x,y. Length = 2x, width (or height) is y.

I will be happy to critique your work or thinking.

## Answer This Question

## Related Questions

- Calculus - A rectangle is bounded by the x-axis and the semicircle y= ã(25-x^2...
- Calculus - A rectangle is bounded by the x-axis and the semicircle y = sqrt(36-x...
- Math - The first question is this: Helen designs a rectangle with an area of 225...
- Calculus - A rectangle is bounded by the x axis and the semicircle = square root...
- calculus - A rectangle is bounded by the x-axis and the semicircle y = ¡Ì36 ¨C ...
- math - a rectangle is twice as long as it is wide. if both of its dimensions are...
- coordinate algebra - The area of a rectangle is found by multiplying the length ...
- Calculus - A rectangle is constructed with its base on the diameter of a ...
- calculus - A rectangle is constructed with its base on the diameter of a ...
- calculus - A Norman window has the shape of a semicircle atop a rectangle so ...

More Related Questions