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October 20, 2014

Homework Help: Calculus

Posted by Tezuka on Friday, October 6, 2006 at 2:49pm.

A rectangle is bounded by the x-axis and the semicircle y=(25-x^2).

Question is, what length and width should the rectangle have so that its area is a maximum, and what is the maxuimum area?



Area= length*width
= 2x*y= 2x*sqrt(25-x^2)

Now, take that, differentiate it, set to zero, and solve for x,y. Length = 2x, width (or height) is y.
I will be happy to critique your work or thinking.

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